1.
Consider
fathers age= f ,sons age = s
Given f=3*s +s =
4s ----1
f+8 =5/2 *(s+8) ----2
f+16=x *(s+16)
From 1 and 2 we can say
that
4s+8=5/2(s+8) => (4s+8)*2 = 5s+40
=> 8s+16=5s+40
=>3s=24 =>s=8
Therefore f=4*8=32
=> f+16= 48 and s+16=24
48 = x *24 =>x=
48/24 => 2 times
2.
Consider
age of younger child = x
Then( x)+(x+3)+(x+6)+(x+9)+(x+12)=50
5x+30=50 => 5x=20
=> X=4
Therefore youngest
child is 4years
3.
F=38
and F=2s => s=19
Sons age before 5 years
= 19-5 = 14years
4.
A=B+2
B=2C => C = B/2
A+B+C= 27
=>B+2+B+B/2=27 => B=10
5. S:
A=5: 4 => S=5X ,A=4X
S+3: A+3=11:9 => S+3=11Y, A+3=9Y
5X=11Y-3, 4X=9Y-3 Solving them we get y=3
A+3=9Y => A=9*3-3=27-3=24
6.
M=24+S
and M+2=2(S+2)
Solving them 2S+2=24+S
=> S=22Years
7. K-6: S-6=6: 5 => K=6X+6, S=5X+6
K+4:
S+4=11: 10=> K=11Y-4, S=10Y-4
=>6X-11Y+10=0,
5X-10Y+10=0
Solving
them we get Y=2
S=10Y-4
= 10*2-4 = 20-4 =16Years
8. F+S=60
F-6=5(S-6)
=>F-6=5S-30 => F=5S-24
From
the above two equations 5S-24+S=60 => 6S=84 =>S =14
Therefore
after six years S=14+6=20years
9. A: D = 4:3 =>A= 4X B=3X
A+6=26
=> A=20
20=4X
So X=5 Therefore D=3*5=15 Years
10. S=R-7
S:
R=7:9 => S=7X, R=9X
7X=9X-7
=>X=7/2
S=
(7)*(7/2) = 24.5Years
11. A: B: C= 4: 7: 9
=> A=4X, B=7X, C=9X
=> A=4X, B=7X, C=9X
(A-8)
+ (B-8) + (C-8) = 56 => A+B+C=80
4X+7X+9X=80 => X=4
So
A = 4*4 = 16, B = 7*4 = 28, C = 9*4 = 36
12. F= 38+A
M=36+B
B=A-4
=> M= 36+A-4 => M=32+A
So
F-M = 38+A-32-A =6Years
13. P = (2/5)*M => 5P=2M
(P+8)=1/2(M+8)
=> 2P+16=M+8 => 2P+8=M
Solving
them we get 5P=2(2P+8) => P=16 So M=16*5/2 =40Years
14.
Data not sufficient to solve
15. F-10 =3(S-10) => F=3S-20
F+10=2(S+10)
=> F=2S+10
ð 3S-20=2S+10 =>S=30 And F=70
ð So F: S= 7:3
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